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CHEM 121 Studioby Learn4Less · UBC CHEM 121

8.3 · Conjugation & colour

Why things are coloured

Absorbed light removes a colour; we see its complement.

By the end you should be able to:

  • Relate the wavelength absorbed to the colour observed

Key idea

Absorbed versus observed colour

White light contains all visible wavelengths (about 400–750 nm). A substance that absorbs part of that range removes those colours, and the light it transmits or reflects looks like the complementary colour, the one opposite on the colour wheel.

  • Absorbs blue light (435–480 nm): looks yellow.
  • Absorbs nothing in the visible: colourless (white as a powder).
  • Absorbs across the whole visible range: black.

In a conjugated molecule the absorption promotes an electron from the HOMO to the LUMO, so the gap ΔE=hc/λ\Delta E = hc/\lambda decides which colour is absorbed.

Formula

From energy gap to colour

λ=hcΔE,hc=1.986×10−25 J m\lambda = \frac{hc}{\Delta E}, \qquad hc = 1.986 \times 10^{-25}\ \text{J m}
Absorbed λ (nm)Colour absorbedColour observed
400–435violetyellow-green
435–480blueyellow
480–490green-blueorange
490–500blue-greenred
500–560greenpurple
560–580yellow-greenviolet
580–595yellowblue
595–650orangegreen-blue
650–750redblue-green

Below 400 nm (UV) or above 750 nm (IR) the absorption is invisible, and the compound looks colourless.

Key idea

Why carrots are orange

β-Carotene has 11 conjugated C=C bonds (22 π electrons), a long enough system for the HOMO–LUMO gap to fall in the visible: λmax⁡\lambda_{\max} = 450 nm. Its absorption is a broad band covering violet, blue and some blue-green light (about 400–500 nm). Removing that whole range leaves yellow, orange and red light, which we see as orange. (Looking up 450 nm alone would suggest yellow; the width of the band matters.)

Lycopene, the red pigment of tomatoes, also has 11 conjugated C=C, but in a flat open chain. It absorbs further into the blue-green (λmax⁡\lambda_{\max} ≈ 470 nm) and looks red. In β-carotene the two C=C inside the end rings are twisted out of the plane, which slightly shortens the effective conjugation.

Key idea

UV absorbers are colourless

Short conjugated systems have large HOMO–LUMO gaps and absorb only ultraviolet light, so they look colourless: ethene (171 nm), 1,3-butadiene (217 nm), benzene (255 nm), 1,3,5,7-octatetraene (290 nm), even 1,3,5,7,9-decapentaene (334 nm).

A simple polyene needs many conjugated double bonds before λmax⁡\lambda_{\max} passes 400 nm, which is why β-carotene, with 11, is coloured and hexatriene, with 3, is not. Sunscreen molecules use this: they are conjugated enough to absorb harmful UV but not visible light, so they are colourless on the skin.

Method

Predicting the colour of a compound

  1. Find λmax⁡\lambda_{\max}: it may be given, or calculate λ=hc/ΔE\lambda = hc/\Delta E and convert metres to nanometres (multiply by 10910^9).
  2. If λ<400\lambda < 400 nm or λ>750\lambda > 750 nm, the compound is colourless.
  3. Find the band in the table: that is the colour absorbed.
  4. The colour observed is the complement in the same row.
  5. Sense check: longer conjugation gives a smaller gap and a longer absorbed wavelength, so the observed colour moves from yellow through orange and red toward purple and blue.

Common mistake

Colour traps

  • Wrong: a dye that absorbs at 450 nm looks blue. Right: it absorbs blue light, so it looks yellow, the complement.
  • Wrong: a larger HOMO–LUMO gap absorbs longer wavelengths. Right: λ=hc/ΔE\lambda = hc/\Delta E, so a larger gap means a shorter wavelength, toward the UV.
  • Wrong: every conjugated molecule is coloured. Right: it must absorb in the visible range. Benzene and hexatriene are conjugated but colourless.

Worked example

Worked example: from gap to colour

A dye has a HOMO–LUMO gap of 3.60×10−193.60 \times 10^{-19} J. What colour is it?

λ=(6.626×10−34)(2.998×108)3.60×10−19=5.52×10−7 m=552 nm\lambda = \frac{(6.626 \times 10^{-34})(2.998 \times 10^{8})}{3.60 \times 10^{-19}} = 5.52 \times 10^{-7}\ \text{m} = 552\ \text{nm}

552 nm lies in the 500–560 nm band: the dye absorbs green light and appears purple.

Chlorophyll absorbs strongly at about 430 nm (violet-blue) and 660 nm (red). The green light in between is not absorbed but reflected, so leaves look green.

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