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CHEM 121 Studioby Learn4Less · UBC CHEM 121

9.1 · Properties & polymers

Intermolecular forces

Dispersion, dipole–dipole and hydrogen bonding.

By the end you should be able to:

  • Identify the intermolecular forces between molecules
  • Rank boiling and melting points and explain the ranking

Key idea

The three intermolecular forces

Intermolecular forces (IMFs) act between molecules. They are much weaker than the covalent bonds within molecules.

  • London dispersion forces: between all molecules and atoms. A momentary uneven electron distribution (an instantaneous dipole) induces a dipole in a neighbour, and the two attract.
  • Dipole–dipole forces: between polar molecules, those with a net dipole moment. The δ+ end of one molecule attracts the δ− end of another.
  • Hydrogen bonding: an especially strong dipole–dipole attraction between an H atom bonded to N, O or F on one molecule and a lone pair on N, O or F of another, as in O–H···O between water molecules.

Ionic compounds are held together by ion–ion attractions, far stronger than any of these: NaCl boils at 1686 K.

Key idea

What makes dispersion forces strong

Dispersion forces depend on polarizability, how easily an electron cloud is distorted.

  • More electrons and larger size give stronger forces: He 4.2 K < Ne 27.1 < Ar 87.3 < Kr 119.9 < Xe 165.0 K, and FX2\ce{F2} 85.0 < ClX2\ce{Cl2} 239.1 < BrX2\ce{Br2} 332.0 < IX2\ce{I2} 457.6 K.
  • Shape and contact area: long, unbranched molecules touch along more of their length than compact, branched ones. For the three CX5HX12\ce{C5H12} isomers: pentane 309.2 K > 2-methylbutane 301.0 K > 2,2-dimethylpropane (neopentane) 282.7 K.
  • For large molecules dispersion can outweigh polarity: nonpolar CClX4\ce{CCl4} (349.9 K) boils above polar CHClX3\ce{CHCl3} (334.3 K).

For molecules of similar size, the usual order of strength is dispersion only < dipole–dipole < hydrogen bonding. Even a hydrogen bond (about 20 kJ/mol in water) is small next to a covalent O–H bond (463 kJ/mol).

Method

Ranking boiling points

  1. Pick out any non-molecular substances first: ionic, metallic and covalent-network substances boil far higher than molecular ones.
  2. For each molecular substance, list its forces: dispersion always; dipole–dipole if the molecule is polar; hydrogen bonding if it has N–H, O–H or F–H.
  3. Similar molar masses: hydrogen bonding > dipole–dipole > dispersion only.
  4. Same kinds of forces: larger molar mass (more electrons) boils higher; for isomers, the less branched one boils higher.
  5. Sense check: a large difference in size can beat polarity or even hydrogen bonding (CHX3I\ce{CH3I} 315.6 K > CHX3F\ce{CH3F} 194.8 K; IX2\ce{I2} 457.6 K > HX2O\ce{H2O} 373.15 K).

Common mistake

Intermolecular-force traps

  • Wrong: boiling water breaks O–H bonds. Right: boiling separates whole molecules; only intermolecular forces are overcome and the H₂O molecules stay intact.
  • Wrong: any molecule containing H and O hydrogen-bonds (dimethyl ether, acetone). Right: the H must be bonded directly to N, O or F. Ethers and ketones are only hydrogen-bond acceptors: they can hydrogen-bond with water, but not with each other.
  • Wrong: CH₄ hydrogen-bonds because it contains H. Right: a C–H bond is not polar enough; methane has only dispersion forces.
  • Wrong: a nonpolar compound always boils below a polar one. Right: size matters too: nonpolar CCl₄ (349.9 K) boils above polar CHCl₃ (334.3 K).

Worked example

Worked example: similar mass, different forces

Rank propane (CX3HX8\ce{C3H8}, 44.1 g/mol), dimethyl ether (CHX3OCHX3\ce{CH3OCH3}, 46.1 g/mol) and ethanol (CHX3CHX2OH\ce{CH3CH2OH}, 46.1 g/mol) by boiling point.

  • The molar masses are similar, so the dispersion forces are similar.
  • Propane is nonpolar: dispersion only, 231.1 K.
  • Dimethyl ether is polar (bent C–O–C), adding dipole–dipole forces. All its H atoms are on carbon, so it cannot hydrogen-bond with itself: 248.3 K.
  • Ethanol has an O–H group and hydrogen-bonds: 351.4 K.

Order: propane < dimethyl ether < ethanol. Ethanol and dimethyl ether are both CX2HX6O\ce{C2H6O}, yet ethanol boils 103 K higher, entirely because of its O–H group.

Worked example

Worked example: the hydrogen-halide anomaly

CompoundBoiling point (K)Strongest type of force
HF292.7hydrogen bonding
HCl188.1dipole–dipole
HBr206.4dipole–dipole
HI237.6dipole–dipole

From HCl to HI the boiling point rises because dispersion forces grow with the size of the halogen, even though the dipoles get smaller. By that trend HF should boil lowest, yet it boils highest because it hydrogen-bonds.

Water and ammonia show the same anomaly: HX2O\ce{H2O} 373.15 K vs HX2S\ce{H2S} 212.8 K, and NHX3\ce{NH3} 239.8 K vs PHX3\ce{PH3} 185.4 K.

Check yourself

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